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Answer:
The midpoint is (3, 3).
Step-by-step explanation:
We are given the two points A(9, 11) and B(-3, -5).
The midpoint is given by:
[tex]\displaystyle M=\Big(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\Big)[/tex]
So:
[tex]\displaystyle M = \Big( \frac{9+(-3) }{2}, \frac{ 11+(-5) }{2} \Big) = (3,3)[/tex]
The midpoint is (3, 3).
We want to show that AM = MB.
We can use the distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]
The distance between A(9, 11) and M(3, 3) will then be:
[tex]AM=\sqrt{(9-3)^2+(11-3)^2}=\sqrt{6^2+8^2}=\sqrt{100}=10[/tex]
And the distance between B(-3, -5) and M(3, 3) will be:
[tex]MB = \sqrt{ (3-(-3))^2 + (3-(-5))^2 } = \sqrt{(6)^2+(8)^2} = \sqrt{ 100 } = 10[/tex]
So, AM = MB = 10.
Since AM = MB = 10, AM + MB = 10 + 10 = 20.
So, we want to prove that AB = 20.
By the distance formula:
[tex]AB=\sqrt{(9-(-3))^2+(11-(-5))^2}=\sqrt{12^2+16^2}}=\sqrt{400}=20\stackrel{\checkmark}{=}20[/tex]