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If ΔFGH ~ ΔKJH, find x.

If ΔFGH ΔKJH Find X class=

Sagot :

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Answer:

x = 16

Explanation:

Since ΔFGH and ΔKJH are similar, let's compare their sides.

So that;

[tex]\frac{GH}{HJ}[/tex] = [tex]\frac{FH}{HK}[/tex]

[tex]\frac{x +8}{32}[/tex] = [tex]\frac{4x-25}{52}[/tex]

cross multiply to have;

32(4x - 25) = 52(x + 8)

128x - 800 = 52x + 416

128x - 52x = 416 + 800

76x = 1216

x = [tex]\frac{1216}{76}[/tex]

  = 16

x = 16

Therefore, x = 16.

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