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Sagot :
Given:
A fair 6 sided die is rolled and then a second fair die is rolled.
To find:
The probability that you roll 1, 2, or 3 on the first die and roll 5 on second.
Solution:
If two fair die are rolled, then the total possible outcomes are
S= {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
So, total outcomes = 36.
Favorable outcomes of getting 1, 2, or 3 on the first die and roll 5 on second are (1,5), (2,5), (3,5).
So, favorable outcomes = 3
We know that
[tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]
[tex]\text{Probability}=\dfrac{3}{36}[/tex]
[tex]\text{Probability}=\dfrac{1}{12}[/tex]
Therefore, the required probability is [tex]\dfrac{1}{12}[/tex].
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