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The length of a rectangle is (3 + √7)m and its width is (1 + 2√7)n. What is the
area of the rectangle?


Sagot :

Answer:

[tex]A=(17+7\sqrt7)\ m^2[/tex]

Step-by-step explanation:

Given that,

The length of the rectangle, [tex]l=(3+\sqrt7)\ m[/tex]

The width of the rectangle, [tex]b=(1+2\sqrt{7} )\ m[/tex]

We need to find the area of the rectangle. We know that the area of the rectangle is given by :

[tex]A=l\times b[/tex]

Put all the values in the above formula.

[tex]A=(3+\sqrt7)\times (1+2\sqrt7)\\\\=3+3\times 2\sqrt7 +\sqrt7+2(\sqrt7)^2\\\\=3+6\sqrt7+\sqrt7+14\\\\=(17+7\sqrt7)\ m^2[/tex]

So, the area of the rectangle is [tex](17+7\sqrt7)\ m^2[/tex].