Answer:
Option (1)
Step-by-step explanation:
Vertex form of the quadratic equation is given by,
y = (x - h)² + k
Where (h, k) is the vertex.
From the graph attached,
Vertex of the parabola is (0, 4).
Therefore, equation of the parabola will be,
y = (x - 0)² + 4
y = x² + 4
Function representing the parabola will be,
f(x) = x² + 4
For the zeros of the quadratic function we find the value of x where f(x) = 0.
x² + 4 = 0
x² = -4
x = ±√(-4)
Since, square root of a negative number is not defined, zeros of the function will be imaginary.
Therefore, both the zeros will be imaginary.
It's clear from the graph, there are no x intercepts of the function Or zeros are imaginary.
Option (1) will be the answer.
