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Answer
B
203.403
Cancel terms that are in both the numerator and denominator
( 2 1 0 0 ) + ( 3 1 ) + ( 4 1/1 0 ) + ( 3 1/1 0 0 0 )
( 2 1 0 0 ) + ( 3 1 ) + ( 2 1/5 ) + ( 3 1/1 0 0 0 )
Solution
( 2 1 0 0 ) + ( 3 1 ) + ( 2 1/5 ) + ( 3 1/1 0 0 0 )