Answered

Connect with knowledgeable experts and enthusiasts on IDNLearn.com. Our community is here to provide detailed and trustworthy answers to any questions you may have.

Sam records the mass of his evaporating dish as 6.488 g. He records the mass of the evaporating dish and the sample of hydrate as 19.72 g. After heating the sample in the evaporating dish to constant weight, the mass of them combined is 11.344 g. How many moles of water were removed from the sample by the heating process?

Sagot :

Answer:

[tex]0.46[/tex] moles of water were removed from the sample by the heating process

Explanation:

Given

Mass of the evaporating dish [tex]= 6.488[/tex] grams

Mass of the sample of hydrate [tex]= 19.72[/tex] grams

Mass of the sample and dish after heating [tex]= 11.344[/tex] grams

The weight of water removed through evaporation

[tex]= 19.72 - 11.344 = 8.376[/tex] grams

Weight of one mole of water [tex]= 18[/tex] grams

Number of moles of water in [tex]8.376[/tex] Grams of water is equal to

[tex]\frac{8.376}{18} = 0.46[/tex] moles

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.