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Sagot :
Answer:
B. {1, 2, 2, 3, 3, 4, 5}
Explanation:
Given
The above code segment
Required
Determine which list does not work
The list that didn't work is [tex]B.\ \{1, 2, 2, 3, 3, 4, 5\}[/tex]
Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3
All other list do not have consecutive duplicate numbers
Option B can be represented as:
[tex]nums[0] = 1[/tex]
[tex]nums[1] = 2[/tex]
[tex]nums[2] = 2[/tex]
[tex]nums[3] = 3[/tex]
[tex]nums[4] = 3[/tex]
[tex]nums[5] = 4[/tex]
[tex]nums[6] = 5[/tex]
if (nums.get(j).equals(nums.get(j + 1)))
The above if condition checks for duplicate numbers.
In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:
[tex]nums[0] = 1[/tex]
[tex]nums[1] = 2[/tex]
[tex]nums[2] = 3[/tex]
[tex]nums[3] = 3[/tex]
[tex]nums[4] = 4[/tex]
[tex]nums[5] = 5[/tex]
The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.
This is so because of the way the if statement is constructed.
There are different kinds of ArrayList of integers. The option in the lists can be passed to remDups to show that the method does not work as intended is {1, 2, 2, 3, 3, 4, 5}.
- When you study the different options given, one will see that that only list B has repeated duplicate numbers such as 2,2 and 3,3. while the other options have only a duplicate numbers that are not following each other.
In Python, there are different ways to remove duplicates from list. An example using naive or novice method is;
The main list is : [1, 3, 5, 6, 3, 5, 6, 1]
The list after deleting duplicates : [1, 3, 5, 6]
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