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What is the vertex of f(x) = 3(x+2)^2 -1

Sagot :

Answer:

[tex]The~vertex~of~parabola~f(x) = a(x-h)^2+k~is~(h,k).\\Given~equation~of~parabola~is:\\f(x) = 3(x+2)^2-1\\So,~ h =-2 ~and~k=-1\\Therefore,~(-2,-1)~is~the~vertex~of~parabola.[/tex]

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