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What is the percent composition of C4H10? (4 points)
44.6% C and 45.4% H
57.3% C and 42.7% H
82.7% C and 17.3% H
89.4% C and 10.6% H​

Sagot :

TutorAnneidn

Answer:82.7% C and 17.3% H

Explanation:

C4 = 12.0107g/mol x 4 = 48.0428 g/mol

H10 = 1.00794 g/mol x 10 = 10.0794 g/mol

Molar Mass of Butane, C4H10 =  48.0428 g/mol + 10.0794 g/mol= 58.1222 g/mol

percent composition of Carbon is  = ( mass of carbon contained in butane / molar mass of Butane) x 100

=(48.0428 /58.1222) x 100% = 0.8265 x 100

=82.65% =82.7% of Carbon.

Percent composition of Hydrogen  = (mass of Hydrogen contained in Butane / molar mass of Butane )x 100  

( 10.0794/58.122 ) x 100% =0.1734 x 100

= 17.3% OF Hydrogen.

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Answer:

C- 82.7% C and 17.3% H

Explanation:

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