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What amount of heat, in kJ, is required to vaporize 163.45 g of ethanol (C₂H₅OH)? (∆Hvap = 43.3 kJ/mol)

Sagot :

Answer:

Amount of heat required = 153.62 J

Explanation:

Given:

Mass = 163.45 g

∆Hvap = 43.3 kJ/mol

Molar mass C₂H₅OH = 46.07 g/mol

Find:

Amount of heat required

Computation:

Amount of heat required = Number of moles x Molar mass C₂H₅OH

Amount of heat required = [163.45/46.07][43.3]

Amount of heat required = 153.62 J

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