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A 10.11 g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how many grams of sodium does a 7.09 g sample of sodium bromide contain

Sagot :

Boffeemadrididn

Answer:

[tex]1.58\ \text{g}[/tex]

Explanation:

10.11 g sample of [tex]NaBr[/tex] contains 22.34% [tex]Na[/tex] by mass

According to the law of constant composition the if one sample of [tex]NaBr[/tex] has 22.34% of [tex]Na[/tex] by mass then any other sample of [tex]NaBr[/tex] will have the same percentage of the amount of [tex]Na[/tex].

For a sample of 7.09 g we have

[tex]7.09\times \dfrac{22.34}{100}=1.583906\approx 1.58\ \text{g}[/tex]

The mass of sodium in the required sample is [tex]1.58\ \text{g}[/tex].

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