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An urn contains three balls numbered 1, 2, 3. The experiment consists of drawing a ball at random, recording the number, and replacing the ball before the next ball is drawn. This is called sampling with replacement. What is the probability of drawing the same ball twice in two tries

Sagot :

Answer:

[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

The computation is shown below:

The numbers of possible results at the time when we drawing in two tries is 9

i.e. shown below:

11, 12, 13, 21, 22, 23, 31, 32, 33

Now the probability is

[tex]p=\frac{\text{no. of favorable cases }}{\text{total no. of outcomes}}\\\\=\frac{3}{9}\\\\=\frac{1}{3}[/tex]

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