IDNLearn.com is your reliable source for expert answers and community insights. Discover the information you need from our experienced professionals who provide accurate and reliable answers to all your questions.
Sagot :
Answer:
Vapor pressure of solution → 151.1 Torr
Option 2.
Explanation:
Raoult's Law is relationed to colligative property about vapor pressure. A determined solute, can make, the vapor pressure of solution decreases.
ΔP = P° . Xm
where Xm is the mole fraction of solute, P° (vapor pressure of pure solvent)
and ΔP = Vapor pressure of pure solvent - Vapor pressure of solution.
In order to determine the vapor pressure of solution, we need to determine, the vapor pressure of B and A in the solution
B's pressure = P° B . Xm
When we add A to B, A works as the solute and B, as the solvent.
Vapor pressure of pure B is 135 torr. (P° B)
In order to determine, the Xm, we use the moles of A and B
Xm = 5.3 mol of B / (1.28 + 5.3) → 0.806
B's pressure = 135 Torr . 0.806 → 108.81 Torr
If mole fraction of B is 0.806, mole fraction for A (solute) will be (1 - 0.806)
A's pressure = 218 Torr . 0.194 → 42.3 Torr
Vapor pressure of solution is sum of vapor pressures of solute + solvent.
Vapor pressure of solution = 42.3 Torr + 108.81 Torr → 151.1 Torr
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.