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write an equation in slope-intercept form for the line that passes through the given point and is parallel to the graph of the given equation. (3,-2),y=x+4

Sagot :

[tex]y=x+4\\\\equation\ of\ line\ parallel\ to \given \one \\\\y=ax+b\\\\ If\ line\ is\ parallel\ a=1\\\\y=x+b\\\\ Substituting\ point\ (3,-2)\\\\ -2=3+b\\-2-3=b\\b=-5\\\\ Equation\ of\ line\ y=x-5 [/tex]
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