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Marta practices the long jump. She jumps the same distance on her first four jumps. Her last two jumps are 1 1/2 feet longer than her first four jumps. Her average jumps distance is 16 feet. The equation below represents the situation, where j is the distance of each of Marta's first four jumps.

4j + 2(j+ 1.5)=16
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6

What is the distance of each of Marta's first four jumps? show work plz.

Sagot :

Answer:

The distance of each of Marta's first four jumps is of 15.5 feet.

Step-by-step explanation:

Average:

The average of a data set is given by the sum of all elements of the data set divided by the number of elements in the data set.

Marta's jumps:

First four of j.

Lax six are 1 1/2 feet longer = 1.5 feet longer, so j + 1.5.

Six jumps, average of 16.

What is the distance of each of Marta's first four jumps?

This is j. So

[tex]\frac{4j + 2(j + 1.5)}{6} = 16[/tex]

[tex]4j + 2j + 3 = 96[/tex]

[tex]6j = 93[/tex]

[tex]j = \frac{93}{6}[/tex]

[tex]j = 15.5[/tex]

The distance of each of Marta's first four jumps is of 15.5 feet.

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