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At a factory that produces pistons for cars, Machine 1 produced 174 satisfactory pistons and 116 unsatisfactory pistons today. Machine 2 produced 180 satisfactory pistons and 20 unsatisfactory pistons today. Suppose that one piston from Machine 1 and one piston from Machine 2 are chosen at random from today's batch. What is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory

Sagot :

Answer:

[tex]0.7[/tex] is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory

Step-by-step explanation:

The two events are independent of each other.

Hence the probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 is equal  probability of choosing satisfactory piston from Machine 1 + probability of choosing unsatisfactory piston from Machine 2

Substituting the given values we get

Probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 =[tex]\frac{174}{174 +116} + \frac{20}{180 +20}[/tex]

=[tex]\frac{174}{174 +116} + \frac{20}{180 +20}[/tex]

=[tex]= \frac{174}{290} + \frac{20}{200}\\= 0.6 + 0.1\\= 0.7[/tex]

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