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Sagot :
Answer:
210N
Explanation:
According to pascal principle
Fb/Ab = Fa/Aa
Given
Fb = 16,170N
Ab = 5,005cm²
Fa = ?
Aa = 65 cm².
Fa is the force that must be exerted on piston A to lift the car
Substitute
16170/5005 = Fa/65
Cross multiply
5005Fa = 65 * 16170
5005Fa = 1,051,050
Fa = 1,051,050/5005
Fa = 210N
Hence the required force is 210N
The force which must be exerted on piston A to lift the car is equal to 210 Newton.
Given the following data:
- Force on piston B = 16,170 newtons
- Area of piston B = 5,005 [tex]cm^2[/tex]
- Area of piston A = 65 [tex]cm^2[/tex]
To determine the force which must be exerted on piston A to lift the car:
Mathematically, the pressure acting on an area is given by the formula:
[tex]Pressure = \frac{Force}{Area}[/tex]
Since, the weight of the car remains constant, the pressure on piston A must be equal to the pressure on piston B.
Pressure A = Pressure B
Mathematically, this given by:
[tex]\frac{F_A}{A_A} = \frac{F_B}{A_B}[/tex]
Making [tex]F_A[/tex] the subject of formula, we have:
[tex]F_A =\frac{A_AF_B}{A_B}[/tex]
Substituting the given parameters into the formula, we have;
[tex]F_A = \frac{65 \times 16170}{5005} \\\\F_A = \frac{1,051,050}{5005}\\\\F_A = 210\;Newton[/tex]
Therefore, the force which must be exerted on piston A to lift the car is equal to 210 Newton.
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