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how to solve 16x2-16x+4=9 using square root property

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[tex]16x^2-16x+4=9 \\ (4x)^2-2 \cdot 2 \cdot 4x + 2^2=9 \\ (4x-2)^2=9 \\ \sqrt{(4x-2)^2}=\sqrt{9} \\ |4x-2|=3 \\ 4x-2=3 \ \lor \ 4x-2=-3 \\ 4x=5 \ \lor \ 4x=-1 \\ x=\frac{5}{4} \ \lor \ x=-\frac{1}{4} \\ \boxed{x \in \{ -\frac{1}{4}, \frac{5}{4} \} }[/tex]
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