Experience the power of community-driven knowledge on IDNLearn.com. Ask anything and receive immediate, well-informed answers from our dedicated community of experts.
Sagot :
.05N+.10D=66.80
D-N=5 --> D=5+N
Substitute
.05N+.10(5+N)=66.80
.05N+.50+.10N=66.80
.15N=66.30
Nickles=442
D-N=5
D-442=5
Dimes=447
Check
.05N+.10D=66.80
.05(442)+.10(447)=66.80
22.10+44.70=66.80
66.80=66.80
442 Nickles and 447 Dimes
D-N=5 --> D=5+N
Substitute
.05N+.10(5+N)=66.80
.05N+.50+.10N=66.80
.15N=66.30
Nickles=442
D-N=5
D-442=5
Dimes=447
Check
.05N+.10D=66.80
.05(442)+.10(447)=66.80
22.10+44.70=66.80
66.80=66.80
442 Nickles and 447 Dimes
Sue deposited 447 dimes and 442 nickels if Sue took her collection of nickels and dimes to deposit in the bank. She has five fewer nickels than dimes.
What is a linear equation?
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
It is given that:
Sue took her collection of nickels and dimes to deposit it in the bank. She has five fewer nickels than dimes.
Her total deposit was $66.80.
Let N and D are the nickels and dimes.
From the question:
D - 5 = N
0.10D + 0.05N = 66.80 (after converting nickels and dimes to dolllars)
Plug D = N + 5 in the second equation:
0.05N +0.10(5 + N) = 66.80
After solving:
0.05N + 0.50 + 0.10N = 66.80
N = 442
D = 447
Thus, Sue deposited 447 dimes and 442 nickels if Sue took her collection of nickels and dimes to deposit in the bank. She has five fewer nickels than dimes.
Learn more about the linear equation here:
brainly.com/question/11897796
#SPJ2
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.