Answered

Get the most out of your questions with the extensive resources available on IDNLearn.com. Join our interactive Q&A community and access a wealth of reliable answers to your most pressing questions.

How do I solve for x in the two equations below using substitution.
4x-2y=4
8x+2y=20

Sagot :

Naǫidn
[tex]4x-2y=4 \\ 8x+2y=20 \\ \\ \hbox{from the 1st equation:} \\ 4x-2y=4 \\ -2y=-4x+4 \\ y=2x-2 \\ \\ \hbox{substitute 2x-2 for y in the 2nd equation:} \\ 8x+2(2x-2)=20 \\ 8x+4x-4=20 \\ 12x=24 \\ x=2 \\ \\ y=2 \cdot 2-2 \\\ y=4-2 \\ y=2 \\ \\ \hbox{the answer:} \\ x=2 \\ y=2[/tex]
Craigc456idn
4x-2y=4
8x+2y=20

12x=24
x=24/12
x=2

sub x into 8x+2y=20
8(2)+2y=20
16+2y=20
2y=20-16
2y=4
y=4/2
y=2

solution (2,2)

check
4x-2y=4(2)-2(2)=4
8x+2y=8(2)+2(2)=16

hope this helps

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.