Answered

From science to arts, IDNLearn.com has the answers to all your questions. Ask anything and receive immediate, well-informed answers from our dedicated community of experts.

Can you help me solve this radical equation √y-10 = y-2 the sqrt sign is only over the y-10

Sagot :

Konrad509idn
[tex]D:y-10\geq0 \wedge y-2\geq0\\ D:y\geq10 \wedge y\geq2\\ D:y\geq10\\\\ \sqrt{y-10}=y-2\\ y-10=(y-2)^2\\ y-10=y^2-4y+4\\ y^2-5y+14=0\\ \Delta=(-5)^2-4\cdot1\cdot14=25-56=-31\\ \Delta<0 \Rightarrow y\in \emptyset[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.