Ziobro267idn
Answered

IDNLearn.com: Where your questions meet expert advice and community insights. Find the solutions you need quickly and accurately with help from our knowledgeable community.

What is the 6th root of 256? ...left in radical notation

Sagot :

Olemakpaduidn
First of all we would break 256 into its simple factors.

2 / 256
2 / 128
2 /  64
2 /  32
2 /  16
2 /    8
2 /    4
2 /    2
        1.

Therefore   256 =  2 * 2 * 2 * 2 *2 * 2 * 2 *2

Therefore sixth root of 256 = [tex] \sqrt[6]{2*2*2*2*2*2*2*2} [/tex]

For every  six 2s we bring out one  out of the root.

= [tex] 2\sqrt[6]{2*2} [/tex]

= [tex] 2\sqrt[6]{4} [/tex]

That's our answer.

We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.