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A rectangle has the height of X and the width of 7X -4

A Rectangle Has The Height Of X And The Width Of 7X 4 class=

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Answer:

Step-by-step explanation:

Area = x(7x-4) = 7x^2-4x

A rectangle has the height or breadth of [tex]X[/tex] and the width or length of  [tex]7X -4[/tex] , then area of rectangle will be   [tex](7X^2-4X)[/tex].

What is rectangle ?

Rectangle is a shape with four sides and having internal angles of  . Two of the sides are longer than the other two. The opposite sides of the rectangle are equal in length.

Area of rectangle [tex]= \text(Length \ * \ Breadth)[/tex]

We have,

Length [tex]=7X-4[/tex]

Breadth [tex]= X[/tex]

So, Using the above formula

Area of rectangle [tex]= \text(Length \ * \ Breadth)[/tex]

                              [tex]=X \ * \ (7X-4)[/tex]

                              [tex]=7X^2 - 4X[/tex]

So, the   Area of rectangle is [tex]7X^2 - 4X[/tex] which is find out using above given formula.

Hence, we can say that a rectangle has the height or breadth of [tex]X[/tex] and the width or length of  [tex]7X -4[/tex] , then area of rectangle will be   [tex](7X^2-4X)[/tex].

To know more about rectangle click here

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