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find the first four terms of the sequence given by the following an=57-4(n-1),n=1,2,3

Sagot :

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Answer:

57, 53, 49, 45

Step-by-step explanation:

Substitute for the n for n=1,2,3,4 so the first term is 57-4(1-1) so =57-4(0) so

a(1) = 57-0 = 57  so that is the 1st term

2nd term 57-4(2-1) so =57-4(1) so   a(2) = 57-4 = 53, etc.

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