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Calculate the number of moles of H2SO4 required to react with 0.93 moles of Al. Do not include units in your answer. Round to the tenths place or further.

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Answer:

1.40 moles of H₂SO₄.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below below:

2Al + 3H₂SO₄ —> Al₂(SO₄)₃ + 3H₂

From the balanced equation above,

2 moles of Al reacted with 3 moles of H₂SO₄.

Finally, we shall determine the number of mole of H₂SO₄ required to react with

0.93 moles of Al. This can be obtained as follow:

From the balanced equation above,

2 moles of Al reacted with 3 moles of H₂SO₄.

Therefore, 0.93 moles of Al will react with = (0.93 × 3)/2 = 1.40 moles of H₂SO₄.

Thus, 1.40 moles of H₂SO₄ is needed for the reaction.

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