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An arithmetic sequence has a 2nd term equal to 3 and 10th term equal to -13.
Find the term of the sequence that has value -93. please answer asap.​

Sagot :

Adioabiolaidn

Answer:

50th term

Step-by-step explanation:

Second term, a + d = 3

Tenth term, a + 9d = -13

a + d = 3 (1)

a + 9d = -13 (2)

Subtract (1) from (2) to eliminate a

9d - d = -13 - 3

8d = -16

d = -16/8

d = -2

Substitute d = -2 into (1)

a + d = 3 (1)

a + (-2) = 3

a - 2 = 3

a = 3 + 2

a = 5

Find the term of the sequence that has value -93.

nth term = a + (n -1)d

-93 = 5 + (n - 1) -2

-93 = 5 + (-2n + 2)

-93 = 5 - 2n + 2

-93 = -2n + 7

-93 - 7 = -2n

-100 = -2n

n = -100/-2

n = 50

50th term = -93

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