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Sagot :
Answer:
[tex]\frac{1}{3}[/tex]
Step-by-step explanation:
[tex]\frac{1}{6}[/tex] + [tex]\frac{1}{6}[/tex]
This is because there is only one "5" and one "6" in a dice. Moreover the total number of numbers in a dice are 6 so the denominator will be 6. Then when the word 'or' is present it means that both the probabilities must be added.
P (of rolling a 5 or 6 on a fair dice) = [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{6}[/tex]
[tex]\frac{2}{6}[/tex] can be simplified further. Both 2 and 6 are factors of 2 so..
[tex]\frac{2}{6}[/tex] = [tex]\frac{1}{3}[/tex]
P (of rolling a 5 or 6 on a fair dice) = [tex]\frac{1}{3}[/tex]
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