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Answer:
one side = 8xy²·[tex]\sqrt{2x}[/tex]
Step-by-step explanation:
if the area is 128x^3y^4 then to find one side you must take the square root
[tex]\sqrt{128}[/tex][tex]\sqrt{x^3}[/tex][tex]\sqrt{y^4}[/tex] = [tex]\sqrt{4}[/tex][tex]\sqrt{32}[/tex][tex]\sqrt{x^2}[/tex][tex]\sqrt{x}[/tex][tex]\sqrt{y^2}[/tex][tex]\sqrt{y^2}[/tex] =
2xy²[tex]\sqrt{16}[/tex][tex]\sqrt{2}[/tex][tex]\sqrt{x}[/tex] =
8xy²·[tex]\sqrt{2x}[/tex]