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Two charged particles exert a force of 0.042 N on each other. Suppose that the particles are moved such that they are now one-eighth as far apart. What is the new force between the particles?

Sagot :

Answer:

New force = 2.688 N

Explanation:

Given that,

Two charged particles exert a force of 0.042 N on each other.

Let the initial distance is r. Later the particles are moved such that they are now one-eighth as far apart.

New distance, r' = (r/8)

The force between particles is given by :

[tex]F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{8})^2}\\\\F'=\dfrac{kq_1q_2}{\dfrac{r^2}{64}}\\\\F'=64\times \dfrac{kq_1q_2}{r^2}\\\\F'=64\times F\\\\F'=64\times 0.042\\\\F'=2.688\ N[/tex]

So, the new force is 2.688 N.

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