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Titanium(IV) chloride decomposes to form titanium and chlorine, like this:

TiCl4(l) → Ti(s)+ 2Cl2(g)

At a certain temperature, a chemist finds that a reaction vessel containing a mixture of titanium(IV) chloride, titanium, and chlorine at equilibrium has the following composition:

Compound Amount
TiCl4 4.18g
Ti 1.32g
Cl2 1.08g

Required:
Calculate the value of the equilibrium constant for this reaction.

Sagot :

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The full question is shown in the image attached to this answer

Answer:

6.2 * 10^-3

Explanation:

The reaction at equilibrium is as follows;

TiCl4(l) → Ti(s)+ 2Cl2(g)

We have to obtain the concentration of chlorine gas as follows;

[Cl2] = 1.08/70.91 g/mol × 5.2 L

[Cl2] = 0.079 M

Kc = [Cl2]^2

Kc = [ 0.079]^2

Kc = 6.2 * 10^-3

View image Pstnonsonjoku
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