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How many moles of electrons are required for denitrifying organism to reduce 78 moles of nitrate to dinitrogen gas?

Sagot :

Drpelezoidn

Answer:

780 moles e⁻

Explanation:

N⁺⁵ in NO₃⁻ requires 2(5e⁻)  => 1/2 mole N₂(g)

That is, NO₃⁻ + 2(5e⁻/mole N₂ formed) => 1/2N₂

NO₃⁻ + 10e⁻/mole N₂ formed => 1/2N₂

∴ 78 mole NO₃⁻ requires 780 moles e⁻  => 1/2(78) moles N₂ = 39 moles N₂

Pstnonsonjokuidn

Denitrification is the reduction of nitrate to dinitrogen gas. It is achieved by denitrifying organism According to stoichiometry, 390 moles of electrons are required to reduce  78 moles of nitrate to dinitrogen gas.

The equation of denitrification;

2 NO3− + 10 e− + 12 H+ → N2 + 6 H2O

From this equation;

2 moles of nitrate requires 10 moles of electrons

78 moles of nitrate requires 78 * 10/2 = 390 moles of electrons

Hence, 390 moles of electrons are required to reduce  78 moles of nitrate to dinitrogen gas.

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