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Calculate the volume in liters of a 0.72 M aluminum sulfate solution that contains 75.0 g of aluminum sulfate Al2SO43.

Sagot :

Maacastrobridn

Answer:

0.30 L

Explanation:

First we convert 75.0 g of Al₂(SO₄)₃ into moles, using its molar mass:

  • 75.0 g ÷ 342.15 g/mol = 0.219 mol Al₂(SO₄)₃

Then we can calculate the volume of the solution, by using the definition of molarity:

  • Molarity = moles of solute / liters of solution
  • 0.72 M = 0.219 mol / Volume

We solve for Volume:

  • Volume = 0.30 L
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