Answered

IDNLearn.com: Your destination for reliable and timely answers to any question. Whether it's a simple query or a complex problem, our community has the answers you need.

A 1.00 L of a solution is prepared by dissolving 125.6 g of NaF in it. What would be the molarity of this solution?

Sagot :

Maacastrobridn

Answer:

2.99 M

Explanation:

In order to solve this problem we need to keep in mind the definition of molarity:

  • Molarity = moles of solute / liters of solution

In order to calculate the moles of solute, we convert 125.6 g of NaF into moles using its molar mass:

  • 125.6 g NaF ÷ 42 g/mol = 2.99 mol NaF

As the volume is already given, we can proceed to calculate the molarity:

  • Molarity = 2.99 mol / 1.00 L = 2.99 M
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.