Answered

IDNLearn.com makes it easy to find precise answers to your specific questions. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.

A point charge gives rise to an electric field with magnitude 1 N/C at a distance of 3 m. If the distance is increased to 6 m, then what will be the new magnitude of the electric field?

Sagot :

Onyebuchinnajiidn

Answer:

The magnitude of the final electric field is 0.5 N/C.

Explanation:

Given;

initial electric field, E₁ = 1 N/C

initial distance moved by the charge, r₁ = 3 m

final distance moved by the charge, r₂ = 6 m

let the magnitude of the final electric field = E₂

The electric potential created by the charge is given as;

V = E₁r₁ = E₂r₂

[tex]E_2 = \frac{E_1r_1}{r_2} \\\\E_2 = \frac{1 N/C\ \times \ 3m}{6m} \\\\E_2 = 0.5 \ N/C[/tex]

Therefore, the magnitude of the final electric field is 0.5 N/C.

Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.