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The angle of elevation to the top of a flagpole is 50 degrees if the angle of elevation was measured 24 m from the flagpoles base wich expression can be used to find the height of the flagpole

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Answer:

Tan 50 = H/24

Step-by-step explanation:

The set up will give a right angled triangle;

Given the following

angle of elevation = 50degrees

Distance of elevation from the flagpole base = 24m (Adjacent)

Required

Height of the flagpole (Opposite) = H

Using the SOH CAH TOA identity

Tan theta = opposite/adjacent

Tan 50 = H/24

H = 24tan50

H = 24(1.1918)

H = 28.60

Hence the required expression is Tan 50 = H/24 where H is the height of the flagpole

The height of the flagpole is 28.60.

Given

The angle of elevation to the top of a flagpole is 50 degrees.

The angle of elevation was measured 24 from the base of the flagpole.

The angle of elevation;

The angle of elevation of the sun is the angle formed between the horizontal line and your line of sight when you look at the sun.

Let the height of the flagpole be H.

Then,

The height of the flagpole is given by;

[tex]\rm Tan\theta=\dfrac{Opposite \ side}{Adjacent \ side}\\\\[/tex]

Substitute all the values in the formula;

[tex]\rm Tan\theta=\dfrac{Opposite \ side}{Adjacent \ side}\\\\ \rm Tan50=\dfrac{H}{24}\\\\H = 24 \times tan50\\\\H = 24\times 1.91\\\\H=28.60[/tex]

Hence, the height of the flagpole is 28.60.

To know more about the angle of elevation click the link given below.

https://brainly.com/question/12992313