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Sagot :
Answer:
electric flux through the entire Gaussian surface will be positive ( + )
Explanation:
The dipole is surrounded by Gaussian surface of charge q
The electric flux will be positive
i.e. Ф = E. ds since the surface is a close one the direction of the area outwardly will be positive . therefore the angle between E and A < 90°
Hence the electric flux through the entire Gaussian surface will be positive
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