IDNLearn.com is the perfect place to get detailed and accurate answers to your questions. Ask anything and receive thorough, reliable answers from our community of experienced professionals.

HELP MEEEE PLEASEEEEEEEEEEEEEE

HELP MEEEE PLEASEEEEEEEEEEEEEE class=

Sagot :

Answer:

a = 4

Step-by-step explanation:

a^2 + b^2 = c^2

a= ?

b= 3

c= 5 (c is always the hypotenuse)

*plug in given values

a^2 + 3^2 = 5^2

a^2 + 9 = 25

-9 -9

a^2 = 16

*find the square root

sqrt(a) = sqrt(16)

a = 4

Answer:

a = 4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

  • a is a leg
  • b is another leg
  • c is the hypotenuse

Step-by-step explanation:

Step 1: Define

Leg a = a

Leg b = 3

Hypotenuse c = 5

Step 2: Solve for a

  1. Substitute in variables [Pythagorean Theorem]:                                          a² + 3² = 5²
  2. [Subtraction Property of Equality] Isolate a term:                                         a² = 5² - 3²
  3. Evaluate exponents:                                                                                       a² = 25 - 9
  4. Subtract:                                                                                                          a² = 16
  5. [Equality Property] Isolate a:                                                                          a = ±4

Since we are dealing with a regular right triangle and not a quadrant triangle, we use the positive root.

∴ a = 4

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.