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5. Find the equation of the line that is
parallel to 8x + 6y +1 = 0 and passing
through the point (-2, 6).

Sagot :

Answer:

[tex]y=-\frac{4}{3} x+\frac{10}{3}[/tex]

Step-by-step explanation:

First, we need to get this in y=mx+b form.

m=slope

b=y axis intercept

8x+6y+1=0

8x+6y=-1

6y=-8x-1

[tex]y=-\frac{4}{3}x-\frac{1}{6}[/tex]

now that we have it in y=mx+b form, we know the slope. For the new equation, the slope will be the same and the only thing we don't know is the y axis intercept, so we'll have to solve for it.

[tex]6=-\frac{4}{3}(-2)+b\\6=\frac{8}{3} +b\\\frac{10}{3}=b[/tex]

Now that we know b, we just put it with the rest of the equation.

[tex]y=-\frac{4}{3} x+\frac{10}{3}[/tex]

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