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y


x

If
y
=
45
when
x
=
81
find,
y
when
x
=
225


Sagot :

Answer:

y = 75

Step-by-step explanation:

Given that:

   y [tex]\alpha[/tex] [tex]\sqrt{x}[/tex]

⇒ y = k[tex]\sqrt{x}[/tex]

where k is the constant of proportionality.

When y = 45, x = 81, then;

45 = k[tex]\sqrt{81}[/tex]

45 = 9 k

k = [tex]\frac{45}{9}[/tex]

  = 5

k = 5

So that,

y = 5[tex]\sqrt{x}[/tex]

the value of y when x = 225 is;

y = 5[tex]\sqrt{x}[/tex]

  = 5 x [tex]\sqrt{225}[/tex]

  = 5 x 15

y = 75

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