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A balloon filled with helium has a volume of 30.0 L at a pressure of 100 kPa and a temperature of 15.0 C. What will the volume of the balloon be if the temperature is increased to 80.0 C and the pressure remains constant? (Hint: Use the Charles law equation)

Sagot :

Answer:

The final volume of the balloon is 24.480 liters.

Explanation:

Let consider that no leakages occur in the balloon during the isobaric process and that helium behaves ideally. From Equation of State for Ideal Gases, we construct the following relationship:

[tex]V_{o}\cdot T_{o} = V_{f}\cdot T_{f}[/tex] (1)

Where:

[tex]V_{o}[/tex], [tex]V_{f}[/tex] - Initial and final volume, measured in liters.

[tex]T_{o}[/tex], [tex]T_{f}[/tex] - Initial and final temperature, measured in Kelvin.

If we know that [tex]V_{o} = 30\,L[/tex], [tex]T_{o} = 288.15\,K[/tex] and [tex]T_{f} = 353.13\,K[/tex], the final volume of the balloon is:

[tex]V_{f} = \frac{V_{o}\cdot T_{o}}{T_{f}}[/tex]

[tex]V_{f} = 24.480\,L[/tex]

The final volume of the balloon is 24.480 liters.

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