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Find the equation of the straight line passing through the point (0, -1) which is perpendicular to the line y=-3/4 x-3

Find The Equation Of The Straight Line Passing Through The Point 0 1 Which Is Perpendicular To The Line Y34 X3 class=

Sagot :

Answer:

y = [tex]\frac{4}{3}[/tex] x - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - [tex]\frac{3}{4}[/tex] x - 3 ← is in slope- intercept form

with slope m = - [tex]\frac{3}{4}[/tex]

Give the slope of a line m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{3}{4} }[/tex] = [tex]\frac{4}{3}[/tex]

The line crosses the y- axis at (0, - 1 ) ⇒ c = - 1

y = [tex]\frac{4}{3}[/tex] x - 1 ← equation of perpendicular line

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