IDNLearn.com is designed to help you find the answers you need quickly and easily. Get accurate and comprehensive answers to your questions from our community of knowledgeable professionals.
Sagot :
[tex] \left \{ {{3x-4y=16\ \ | * (-5)} \atop {5x+6y=14 \ \ | *3}} \right. \\\\ \left \{ {{-15x+20y=-80} \atop {15x+18y=42}} \right. \\+-----\\add\ both \ equations\\\\
38y=-38\ \ \ | divide\ by\ 38\\\\
y=-1\\\\
3x=16+4y\\\\
x=\frac{16+4y}{3}=\frac{16+4*(-1)}{3}=\frac{12}{3}=4\\\\ \left \{ {{y=-1} \atop {x=4}} \right. [/tex]
okay for this one, i will start with x
3x - 4y = 16
5x + 6y = 14
I will multiply the top row with (-5) and the bottom with (3)
so the new equation is
-15x + 20y = -80
15x + 18y = 42
After canceling (x) the new equation will be
38y = -38
Divide by 38
And you will get -1
Now substitute (-1) to (y) to the old equation ( any of the old equation)
3x- 4(-1)= 16
x = 4
answers ( 4, -1)
3x - 4y = 16
5x + 6y = 14
I will multiply the top row with (-5) and the bottom with (3)
so the new equation is
-15x + 20y = -80
15x + 18y = 42
After canceling (x) the new equation will be
38y = -38
Divide by 38
And you will get -1
Now substitute (-1) to (y) to the old equation ( any of the old equation)
3x- 4(-1)= 16
x = 4
answers ( 4, -1)
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.