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There are 12 pieces of candy in a bowl. 6 are mints, 4 are Butterscotch, and 2 are Cinnamon.

What is the probability of Mr. Binder pulling
Butterscotch from the bowl, putting it back, and
then choosing mint? P(Butterscotch, then mint)

Sagot :

Mathstudent55idn

Answer:

1/6

Step-by-step explanation:

total = 12

number of butterscotch = 4

number of mint = 6

Since he replaces the mint, these events are independent events.

p(butterscotch, then mint) = p(butterscotch) * p(mint)

p(event) = (number of desired outcomes)/(total number of outcomes)

p(butterscotch) = 4/12 = 1/3

p(mint) = 6/12 = 1/2

p(butterscotch, then mint) = p(butterscotch) * p(mint)

p(butterscotch, then mint) = 1/3 * 1/2

p(butterscotch, then mint) = 1/6

Answer: 1/6

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