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Sagot :
Answer:
25 fudge centres, 20 nut clusters, 18 truffles, 6 of each type of chocolate
Step-by-step explanation:
Michel has a total of $15.00
So, if he only has to buy one type, we just divide the total amount by the price, like this:
[tex]\frac{15.00}{0.60}[/tex] = 25 fudge centres
[tex]\frac{15.00}{0.75}[/tex] = 20 nut clusters
[tex]\frac{15.00}{0.80}[/tex] = 18.75, so we round down = 18 truffles
If he buys the same of number of each type, we know that:
0.60x + 0.75x + 0.80x ≤ $15.00
2.15x ≤ 15.00
x ≤ 6.977...
This means that Michel can only buy 6 of each type of chocolate.
Answer:
If he buys only one type, he can buy 25 fudge centers OR 20 nut clusters OR 18 truffles.
The equations you can write to solve those are:
0.6f = 15
0.75n = 15
0.8t = 15
If he buys an equal number of each then
0.6f + 0.75n + 0.8t = 15
and
f = n = t
He can buy 6 of each without going over his budget.
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