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help me ez not that hard ty

Help Me Ez Not That Hard Ty class=

Sagot :

Answer:

a) x= 13 and x=0

b) x= 3 and x= 6

c) x= -2 ± [tex]\sqrt[/tex]34

d) x= 5.5 and x= 1.5

Step-by-step explanation:

To find the x values in a quadratic equation you must follow these steps.

First, subtract the c value from both sides:

(I am using letter a as an example)

[tex]x^{2} -13x=0[/tex]

Then, half the b value and write it down:

[tex]x^{2} -13x=0\\-6.5x[/tex]

Next, square the answer to the last step. In this case, -6.5:

[tex]x^{2} -13x= 0\\-6.5 \\42.25[/tex]

Next, insert the answer to the previous question into the equation by adding it to both sides:

[tex]x^{2} -13x+42.25=42.25[/tex]

Next, you place x in the parenthesis with half of the b value and use the the number after the equals sign in your equation as the answer. I know that my explanation is confusing but the example below should help it make sense:

[tex](x-6.5)^2=42.25[/tex]

Then, square root both sides of the equation making the answer after the parenthesis plus or minus:

x- 6.5 = ± 6.5

Finally, solve each side for positive or negative to get your two answers:

[tex]x-6.5= 6.5\\x=13[/tex]                                          [tex]x-6.5= -6.5\\x=0[/tex]

If the value in the square rooting step is not a perfect square, leave the value underneath the square root symbol and proceed as before to get ONE answer. Like in answer C.