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What is the height of a 2.0 kilogram ball that is held above the floor and has 39 joules of potential energy ?

Sagot :

Answer:

Answer: the height h is 1.95 m above the floor

Explanation:

m = 2.0 kilogram

Ep = 39 J

g = 10 m/s²

h = ?

Ep = mgh

h = Ep ÷ mg

h = 39 ÷ (2×10)

h = 39÷20

h = 1.95 m

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