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Sagot :
The speed of the first butterfly is 70 m/min, while the speed of the second butterfly is 80 m/min
Represent the speed of the first butterfly with x.
Given that the flowerbeds are 560 meters apart, and rate of one butterfly is 10m/min greater than the other
Then, we have:
[tex]B_1 = \frac{560}{x}[/tex]
[tex]B_2 = 1 + \frac{560}{x+10}[/tex]
Equate both equations
[tex]1 + \frac{560}{x+10} = \frac{560}{x}[/tex]
Using a graphing calculator, we have:
[tex]x = 70[/tex]
Also, we have:
[tex]x + 10 = 80[/tex]
This means that, the speed of the first butterfly is 70 m/min, while the speed of the second butterfly is 80 m/min
Read more about speed and rates at:
https://brainly.com/question/19493296
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