Answered

Connect with knowledgeable individuals and find the best answers at IDNLearn.com. Discover in-depth answers from knowledgeable professionals, providing you with the information you need.

Two butterflies simultaneously leave an aster flowerbed and fly to a rose flowerbed. One butterfly flies 10 m/min faster than the other, and so lands on a rose 1 minute earlier. Find the speed of each butterfly if the flowerbeds are 560m apart

Sagot :

MrRoyalidn

The speed of the first butterfly is 70 m/min, while the speed of the second butterfly is 80 m/min

Represent the speed of the first butterfly with x.

Given that the flowerbeds are 560 meters apart, and rate of one butterfly is 10m/min greater than the other

Then, we have:

[tex]B_1 = \frac{560}{x}[/tex]

[tex]B_2 = 1 + \frac{560}{x+10}[/tex]

Equate both equations

[tex]1 + \frac{560}{x+10} = \frac{560}{x}[/tex]

Using a graphing calculator, we have:

[tex]x = 70[/tex]

Also, we have:

[tex]x + 10 = 80[/tex]

This means that, the speed of the first butterfly is 70 m/min, while the speed of the second butterfly is 80 m/min

Read more about speed and rates at:

https://brainly.com/question/19493296

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions deserve precise answers. Thank you for visiting IDNLearn.com, and see you again soon for more helpful information.