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If CD = 7√3, find AE

I give you 25, PLSS HELPPP

If CD 73 Find AE I Give You 25 PLSS HELPPP class=

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Answer:

AE = 22.86

Step-by-step explanation:

In triangle CDE

cos 30° = CD/CE

[tex] \frac{\sqrt 3}{2} = \frac {7\sqrt 3}{CE}[/tex]

[tex]CE= {7\sqrt 3}\times \frac{2}{\sqrt 3} [/tex]

[tex]CE= 14 [/tex]

In triangle BCE

sin 45° = CE/BE

[tex] \frac{1}{\sqrt 2}= \frac{14}{BE}[/tex]

[tex]BE= 14\sqrt 2[/tex]

In triangle ABE

sin 60° = BE/AE

[tex] \frac{\sqrt 3}{2}= \frac{14\sqrt 2}{AE}[/tex]

[tex]AE= 14\sqrt 2\times\frac{2}{\sqrt 3} [/tex]

[tex]AE= \frac{28\sqrt 2}{\sqrt 3} [/tex]

[tex]AE= \frac{28\sqrt 6}{ 3} [/tex]

[tex]AE= \frac{68.5857128}{ 3} [/tex]

AE = 22.8619043

AE = 22.86

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