Answered

Find solutions to your questions with the help of IDNLearn.com's expert community. Ask your questions and receive reliable, detailed answers from our dedicated community of experts.

How many moles of water formed from 3.4 moles of oxygen?







2. How many moles of carbon dioxide produced from 5.2 moles of butane?







3. How many moles of water produced from 25.6 moles of butane?





4Na + O2 à 2Na2O Use this equation to answer questions 4 and 5.

4. How many moles of oxygen are required to completely react with 9.5 g of sodium?







5. How many grams of sodium are required to produce 12.5 grams of sodium oxide?







2NaOH + H2SO4 à 2H2O + Na2SO4

6. How many moles of sodium sulfate are formed if you start from 200 grams of sodium hydroxide and an excess of sulfuric acid?







7. If 8 g of sodium sulfate was produced from the reaction shown how many grams of sulfuric acid was used as a reactant?












Pb(SO4)2 + 4LiNO3 à Pb(NO3)4 + 2Li2SO4

8. How many grams of lithium nitrate will be needed to make 250 grams of lead (lV) nitrate assuming that you have adequate amount of lithium nitrate?











2Fe2O3 + 3C à 4Fe + 3CO2
9 Calculate the theoretical yield of iron in grams produced from 5.67 g of iron (lll) oxide.














10. Calculate the number of atoms of iron produced from 100.0 g of iron (lll) oxide.

Sagot :

Answer: a. 6.8 moles of water

b. 41.6 moles of carbon dioxide

Explanation:

The balanced chemical equation for formation of water is:

[tex]2H_2+O_2\rightarrow 2H_2O[/tex]  

According to stoichiometry :  

1 mole of [tex]O_2[/tex] produces = 2 moles of [tex]H_2O[/tex]

Thus 3.4 moles of [tex]O_2[/tex] produce =[tex]\frac{2}{1}\times 3.4=6.8moles[/tex]  of [tex]H_2O[/tex]

The balanced chemical equation for combustion of butane is:

[tex]2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O[/tex]  

According to stoichiometry :  

1 mole of butane produces = 8 moles of [tex]CO_2[/tex]

Thus 5.2 moles of butane produce =[tex]\frac{8}{1}\times 5.2=41.6moles[/tex]  of [tex]CO_2[/tex]

Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.